Supertype of enumeration

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Supertype of enumeration

Supertype of enumeration

Feb-10-11 13:51:45

Hello,
Is it possible to declare a new enumeration as being a supertype of an existing enumeration ? So that when the base enumeration is modified, the second takes it into account.
I can't find a syntax that would work, nor any help on the subject.
Thanks,
JB.

For example:
type BaseEnumeration=enumeration(base1,base2,base3);
type CompletedEnumeration=enumeration(base1,base2,base3,comp1,comp2); //as =BaseEnumeration added of comp1,comp2

JB: 6 Posts; Thank you [ 0 ]

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Re: Supertype of enumeration

Feb-10-11 14:44:39

The only way I could think of was the following, but it won't work because you may only inherit from one class of type restriction.

Code:

class A

  type E1 = enumeration(a,b,c);

  type E2 = enumeration(d,e,f);

  type F

    extends E1;

    extends E2;

  end F;

  F f;

end A;

The following does flatten, but won't produce correct code:

Code:

class A

  class E1 = enumeration(a,b,c);

  class E2 = enumeration(d,e,f);

  class F

    extends E1;

    extends E2;

  end F;

  F f;

end A;

sjoelund.se: 1700 Posts; Thank you [ 159 ]

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